Question

Equal weights of carbon and oxygen are heated in a closed vessel producing CO and CO2 in a 1: 1 mol ratio. Find which component is limiting and which component left and what is its percentage out of total weight taken?
​

Answer 1

Answer:

Let, 1 mole of each of

P

2

O

5

and

P

2

O

3

is formed. So the mole ratio of the reacting P and O atoms is 4:8 or 1:2

Let the mass of oxygen and phosphorus atoms be

W

.

Therfore, moles of oxygen atoms =

W

16

moles of phosphorus atoms =

W

31

From the mole ratio,

2 moles of oxygen atoms combine with 1 mole of phosphorus atoms.

∴

W

16

moles of oxygen atoms combine with

W

32

moles of phosphorus atoms.

So here phosphorus is the excess component.

So, moles of phosphorus remaining

=

W

31

−

W

32

Hence mole parcentage of the excess component

=

(

W

31

−

W

32

)

W

31

×

100

=

1

32

×

100

=

3.125

%

Explanation:

Hope it helps u