Equal weights of ethane and hydrogen are mixed in an empty container at 25°C. The fraction of the total pressure exerted by hydrogen is (a) 1 : 2 (b) 1 : 1(c) 1 : 16 (d) 15 : 16
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Let x g of each gas is mixed.
Mole of ethane = x/30
Mole of hydrogen = x/2
Mole fraction of hydrogen=(x/2)/(x/2 + x/30)= 15/16
⇒ (Partical pressure of H_2)/(Total pressure) = mole fraction of hydrogen = 15 : 16
Let x g of each gas is mixed.
Mole of ethane = x/30
Mole of hydrogen = x/2
Mole fraction of hydrogen=(x/2)/(x/2 + x/30)= 15/16
⇒ (Partical pressure of H_2)/(Total pressure) = mole fraction of hydrogen = 15 : 16
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