Question

Equal weights of P4 and O2 were heated to form P406 and P4010. In what mola
products will be formed if no reactant is left.​

Answer 1

Answer:

2P4 + 8O2 - P4O6 + P4O10 , i.e.,

248g(P) + 256g(O) - (124g P+96g O)

+ (124g P+160g O)

So, according to the question, we would take 2P4 weight to be 31g.

:. P4 — 15.5g

Similarly,

8O2 — 32g

:. O6 (3O2) — (3 ×32)/8 =12g

:.O10 (5O2) — (5×32)/8 = 20g

So, weight of P406 would be-

15.5 + 12 = 27.5g

Weight of P4O10 -

15.5 + 20 = 35.5g