Question

Equal weights of two gases of molecular weigh 4 and 40 are mixed. The pressure of the mixture is 1.1atm. The partial pressure of the lught gas in this mixture is

Answer 1

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Q.) Equal weights of two gases of molecular weigh 4 and 40 are mixed. The pressure of the mixture is 1.1atm. The partial pressure of the lught gas in this mixture is .


Ans.) Number of moles of lighter gas =
$\frac{m}{4}$

Number of moles of heavier gas =
$\frac{m}{40}$


Total Number of moles =
$\frac{m}{4} + \frac{m}{40} = \frac{11m}{40}$

Mole fraction of lighter gas =
$\frac{m}{40} \times \frac{40}{11m} = \frac{10}{11}$

Partial pressure due to lighter gas = Po ×
$\frac{10}{11}$

=)
$1.1 \times \frac{10}{11}$
=) 1 atm .


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Answer 2

Answer:

Explanation:

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Partial pressure is 1atm