equate -2b-c=-1 and b+c=0
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• -2b-c=-1
=> -(2b+c)=-1
=> 2b+c=1 -(i)
• b+c=0 -(ii)
From (ii),
b=0-c
Substitute this value of b in (i),
2(0-c)+c=1
0-2c+c=1
-c=1
Use value of c in (ii),
b+(-1)=0
b-1=0
b=0+1
Therefore, value of b= 1 and c= -1
Answered by
6
• -2b-c=-1
=> -(2b+c)=-1
=> 2b+c=1 -(i)
• b+c=0 -(ii)
From (ii),
b=0-c
Substitute this value of b in (i),
2(0-c)+c=1
0-2c+c=1
-c=1
Use value of c in (ii),
b+(-1)=0
b-1=0
b=0+1
Therefore, value of b= 1 and c= -1
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