Question

Equate: 9^n * 3^2*3^n-(27)^n/(3^3)^5*2^3=1/27

Answer 1

Answer:

Given (9n × 32 × 3n – (27)n)/ (33)5 × 23 = (1/27) = (32)n × 33 × 3n – (33)n/ (315 × 23) = (1/27) = 3(2n+2+n) – (33)n/ (315 × 23) = (1/27) = 3(3n+2)– (33)n/ (315 × 23) = (1/27) = 33n × 32 – 33n/ (315 × 23) = (1/27) = 33n × (32 – 1)/ (315 × 23) = (1/27)

Answer 2

Answer:

I can't understand