equation 1 : x+y = 200 equation 2: 500x+100y=80000
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x+y=200
500x+100y=80000 dividing by 100 gives (5x+y=800)
Therefore, eq1: x+y=200
.................. eq2: 5x+y=800
Subtracting eq1 from eq2 gives
........... 4x=600
............ x=150
Putting value of x in eq1
150+y=200
......... y=50
Therefore, x=150 and y=50
500x+100y=80000 dividing by 100 gives (5x+y=800)
Therefore, eq1: x+y=200
.................. eq2: 5x+y=800
Subtracting eq1 from eq2 gives
........... 4x=600
............ x=150
Putting value of x in eq1
150+y=200
......... y=50
Therefore, x=150 and y=50
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