Question

equation 2x^2-4x+5=0has. 1. two real roots
2.no real root
3. two equal roots
4.can't say ​

Answer 1

Answer:

2.no real root

Step-by-step explanation:

D(discriminant)=b²-4ac=(-4)²-4x2x5=16-40=-24

We know that if the discriminant is negative, the equation has 2 unreal roots.

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Answer 2

$\huge\underline\mathbb{\red S\pink{O}\purple{LU} \blue{T} \orange{IO}\green{N :}}$

★ Given that,

The equation 2x² - 4x + 5 = 0 has.

★ Let,

• a = 2
• b = - 4
• c = 5

$\sf\: By\:using\:discrimination\:formula$

$\sf\purple{↪ (∆) = b² - 4ac}$

• Substitute the values.

$\tt\:⟹ (- 4)² - 4(2)(5)$

$\tt\:⟹ 16 - 40$

$\tt\:⟹ - 24$

$\underline{\boxed{\bf{\blue{∴ (∆) < 0, since\:they\:are\:no\:real\:roots.}}}}$