Math, asked by malar2002, 10 months ago

equation 3x^3+5x^2=3x+5 has got 3 roots and hence the factors of the left hand side of the equation 3x^3+5x^2-3x-5=0 are​

Answers

Answered by mhanifa
15

Answer:

-1, 1, -5/3

Step-by-step explanation:

  • 3x^3+5x^2-3x-5=0
  • 3x^3-3x+5x^2-5=0
  • 3x(x^2-1)+5(x^2-1)=0
  • (x^2-1)(3x+5)=0
  • (x + 1) (x - 1) (3x + 5)=0
  • x+1= 0, x= -1
  • x-1= 0,  x= 1
  • 3x+5=0, 3x=-5, x= -5/3

Roots are: -1, 1, -5/3

Factors are: (x + 1) (x - 1) (3x + 5)=0

Answered by Aditiiiiiiiiiii
7

Answer:

x= -1 & x = 1 & x= -5/3

Step-by-step explanation:

...............................

Attachments:
Similar questions