Question

Equation for finding the three consecutive even numbers whose sum is 66

Answer 1

Now, one would definitely take the smallest number as x or something else.
But it is wrong as we know that the basic formation of an even number is 2n.

So, let the smallest number be 2n.
Thus, other two numbers are 2n+2 and 2n+4.

By condition,
2n +(2n+2)+ (2n+4) = 66.
Or, 6n + 6 = 66.
Or, 6(n+1) = 66.
Or, n+1 = 66/6 = 11.
Or, n = 11 - 1 = 10.

Thus the there number are,
2n = 2*10 = 20.
2n+2 = 2*10 + 2 = 22.
2n+4 = 2*10 + 4 = 24.

Now, the numbers are 20, 22 and 24.

If helps, please mark it as brainliest ^_^

Answer 2

Let the three consecutive even number be X , (X+2) and (X+4).

Sum of three consecutive even number is 66.


According to the question,

X+(X+2)+(X+4)=66
=>X+X+2+X+4=66
=> 3x+6 =66
=> 3x = 66-6
3x = 60
X = 60/3
= 20
Hence, three consecutive even number are 20 and 20+2=22 and 20+4=24.