Question

Equation for the statement " Sum of four times y and 12 is 20" *
1 point
4 y+12 = 20
4(y+12) = 20
4+y+12 = 20
4 y = 32
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Answer 1

Answer:

y = 2

Step-by-step explanation:

4y + 12 = 20

4(y+3) = 20(factorising 4 from both the terms)

y+3 = 20/4(dividing both sides by 4)

y + 3 = 5

y = 5-3(subtracting both sides by 3)

y = 2