Question

Equation of 2x_3y_17=0,4x_y_13=0

Answer 1

Given:

2x-3y-17=0

4x-y-13=0

To find:

x,y

Solution:

$\bold{ 2x-3y-17=0}\\\\\to2x-3y=17....(a)\\\\\bold{4x-y-13=0}\\\\\to 4x-y=13...(b)$

Solve the equation (a) and put the value into equation (b):

$\to 2x-3y=17\\\\\to 2x= 17+3y\\\\\to x= \frac{17+3y}{2}....(c)$

$\bold{4x-y=13} \ \ \ equation \ b \ \\\\\to 4\times( \frac{17+3y}{2})-y=13\\\\\to 2(17+3y)-y=13\\\\\to 34+6y-y=13\\\\\to 34+5y-13=0\\\\\to 21+5y\\\\\to y=-\frac{21}{5} \\\\ \to y= - 4.2$

Put the value of y into the equation c:

$\bold{x=\frac{17+3y}{2}} \ \ \ equation \\\\\to x=\frac{17+3 \times (-4.2) }{2}\\\\\to x=\frac{17-12.6 }{2}\\\\\to x= \fradc{4.4}{2}\\\\\to x= 2.2$

The final value of x and y is "2.2 and -4.2".