Question

Equation of a circle passing through the intersection of line 3x-2y-1=0 and 4x-y-27=0 and its center is (2,-3) find equation of circle.

Answer 1

Step-by-step explanation:

Solving 3x – 2y = 1 and 4x + y = 27 Simultaneously, we get x = 5 and y = 7 ∴ The point of intersection of the lines is (5, 7) Now we have to find the equation of a circle whose centre is (2, -3) and which passes through (5, 7) Radius = √((5 - 2)2 + (7 + 3)2) = √(9 + 100) = √109 ∴ Required equation of the circle is (x – 2)2 + (y + 3)2 = (√109)2 ⇒ x2 + y2 – 4x + 6y – 96 =0

Answer 2

Answer:

Solving 3x - 2y = 1 and 4x + y = 27 Simultaneously, we get x = 5 and y = 7: The point of intersection of the lines is (5, 7) Now we have to find the equation of a circle whose centre is (2, -3) and which passes through (5, 7) Radius = √((5 - 2)2 + (7 + 3)2) = √(9 + 100)=√109. Required equation of the circle is (x - 2)2 +

Step-by-step explanation:

=(√109)2 ⇒ x2 + y2 - 4x + 6y - 96 =0