Math, asked by AgentOT7, 3 months ago

Equation of a circle which passes through (3, 6)
and touches the axes is _______ .
(A) x² + y² + 6x + 6y + 3 = 0
(B) x² + y² - 6x - 6y - 9 = 0
(C) x² + y² - 6x - 6y + 9 = 0
(D) x² + y² - 6x + 6y - 3 = 0

Give answer with solution. ​

Answers

Answered by rehankhan41600
0

I don't know know question

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