Question

Equation of a circle which passes through the point (3, 6) and touches the axes is​

Answer 1

Answer:

The equation of circle touching both axes is

x

2

+y

2

−2px−2py+p

2

=0________ (1)

since, the circle passes through point (3+6)

Therefore , (3)

2

+(−6)

2

−2p×3−2p×6+p

2

=0

9+36−6p−12p+p

2

=0

45−8p+p

2

=0

p=15,3

Hence, equation of the circle will be

x

2

+y

2

−6x−6y+9=0 or x

2

+y

2

−30x−30y+225=0

Step-by-step explanation:

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Answer 2

Answer:

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Step-by-step explanation:

The equation of circle touching both axes is

x^2 +y^2 −2px−2py+p^2 =0________ (1)

since, the circle passes through point (3+6)

Therefore , (3)^2 +(−6)^2 −2p×3−2p×6+p^2 =0

9+36−6p−12p+p^2 =0

45−8p+p^2 =0

p=15,3

Hence, equation of the circle will be

x^2 +y^2 −6x−6y+9=0 or

x^2 +y^2 −30x−30y+225=0