Question

equation of a line is 2x+3y-4=0. find its x and y intersect

Answer 1

Step-by-step explanation:

We solve the given line 2x+3y=4 for y as follows:

2x+3y=4⇒3y=−2x+4⇒y=3−2x+4⇒y=−32x+34

m=−32 and c=34

Answer 2

You mean the x-intercept and the y-intercept.

First, convert this equation into slope-intercept form.

2x + 3y + 4 = 0

Subtract 4 and 2x from both sides:

3y = -2x-4

Divide both sides by 3:

y = -2/3x - 4/3

Set x equal to zero to find the y-intercept:

y = -2/3*0 - 4/3

y = -4/3

Thus, the y-intercept is at (0, -4/3)

Now, set y equal to zero to find the x-intercept. You do this by solving for x when y = 0.

y = -2/3x - 4/3

y = 0

0 = -2/3x - 4/3

Add 4/3 to both sides:

4/3 = -2/3x

Multiply both sides by 3 to get rid of the fractions:

4 = -2x

Divide both sides by -2:

x = -2

Thus, the x-intercept is at (-2,0)

here is your answer!

hope it helps you ♡´･ᴗ･`♡

mark as brainliest ❀