Question

Equation of a line is x - y √3 + 6 =0, convert this equation to a perpendicular form.

Answer 1

Answer:

Step-by-step explanation:

Where is the value of x and y without that eq would not from

Answer 2

$\bold{\huge{Hay!!}}$


$\bold{Dear\:user!!}$


$\bold{\underline{Question-}}$


Equation of a line is x - y √3 + 6 =0, convert this equation to a perpendicular form.


$\bold{\underline{Answer-}}$


Given equation is
$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: x - y \sqrt{3} + 6 = 0$

$x - y \sqrt{3} = - 6$

$dividing \: the \: both \: sides \: with \: \\ \sqrt{( {1}^{2}) + ( - \sqrt{3)} {}^{2} } \\ \\ = \sqrt{1 + 3} \\ \\ = \sqrt{4} = 2$


$= > \frac{1}{2} x - \frac{ \sqrt{3} }{2} y = - \frac{6}{2} \\ \\ - \frac{1}{2} x + \frac{ \sqrt{3} }{2} y = 3 \\ \\ \\ \\ x \: cos120 \: + y \: sin \: 120 = 3$