Question

Equation of a line passing through
(1,2) and parallel to the line y = 3x - 1 is
​

Answer 1

Answer:

y=3x−1y=3x−1

=>3x−y−1=0=>3x−y−1=0

A line which is parallel to another will have same slope.

The slope of the line Ax+By+c=0Ax+By+c=0is given by −BA−BA

Hence, a line parallel to the line Ax+By+C=0Ax+By+C=0is given by Ax+By+K=0Ax+By+K=0

=>3x−y+K=0=>3x−y+K=0is a line parallel to 3x−y−1=03x−y−1=0

It is given that the required line passes through (0,0)(0,0)

i.e. 3x−y+K=03x−y+K=0passes through (0,0)(0,0)

=>3⋅0−0+K=0=>3⋅0−0+K=0

=>K=0=>K=0

=>3x−y=0=>3x−y=0 is the required line.

or y=3xy=3xis the required line.