Question

equation of a line passing through (2,0) and parallel to x+y+1=0 is I want the equation parallel to this
please say with explanation ​

Answer 1

Answer:

Correct option is

A

2x−3y=−5

First we find the slope of the line 2x−3y+8=0 by placing it into slope intercept form:

2x−3y+8=0

⇒−3y=−2x−8

⇒3y=2x+8

⇒y=  

3

2

​  

x+  

3

8

​  

 

Therefore, the slope of the line is m=  

3

2

​  

.

Now since the equation of the line with slope m passing through a point (x  

1

​  

,y  

1

​  

) is

y−y  

1

​  

=m(x−x  

1

​  

)

Here the point is (2,3) and slope is m=  

3

2

​  

, therefore, the equation of the line is:

y−3=  

3

2

​  

(x−2)

⇒3(y−3)=2(x−2)

⇒3y−9=2x−4

⇒2x−3y=−9+4

⇒2x−3y=−5

Hence, the equation of the line is 2x−3y=−5.

Answer 2

Answer:

Correct option is

A

2x−3y=−5

First we find the slope of the line 2x−3y+8=0 by placing it into slope intercept form:

2x−3y+8=0

⇒−3y=−2x−8

⇒3y=2x+8

⇒y=  

3

2

​  

x+  

3

8

​  

 

Therefore, the slope of the line is m=  

3

2

​  

.

Now since the equation of the line with slope m passing through a point (x  

1

​  

,y  

1

​  

) is

y−y  

1

​  

=m(x−x  

1

​  

)

Here the point is (2,3) and slope is m=  

3

2

​  

, therefore, the equation of the line is:

y−3=  

3

2

​  

(x−2)

⇒3(y−3)=2(x−2)

⇒3y−9=2x−4

⇒2x−3y=−9+4

⇒2x−3y=−5

Hence, the equation of the line is 2x−3y=−5.

Step-by-step explanation: