Math, asked by ayushisingh8bkv, 3 days ago

Equation of a line passing through origin is (a) x + y = 1
(b) x = 2y – 4
(c) x + y = 0
(d) y = x – 1​

Answers

Answered by Anonymous
13

Equation of a line passing through origin is

(a) x + y = 1

(b) x = 2y – 4

(c) x + y = 0

(d) y = x – 1

___________________________

For equation x + y = 1 (a)

~ Let us put x as 0 first in (a)

→ x + y = 1

→ 0 + y = 1

→ y = 1

  • Henceforth, coordinates (0,1)

~ Now let's put y as 0 in (a)

→ x + y = 1

→ x + 0 = 1

→ x = 1

  • Henceforth, coordinates (1,0)

Refer to attachment first!

___________________________

For equation x = 2y – 4 (b)

~ Let us put x as 0 first in (b)

→ x = 2y - 4

→ 0 = 2y - 4

→ 0 + 4 = 2y

→ 4 = 2y

→ 4/2 = y

→ y = 2

  • Henceforth, coordinates (0,2)

~ Now let us put y as 0 in (b)

→ x = 2y - 4

→ x = 2(0) - 4

→ x = 0 - 4

→ x = -4

  • Henceforth, coordinates (-4,0)

Refer to attachment second!

___________________________

For equation x + y = 0 (c)

~ Firstly let us put x as 0!

→ x + y = 0

→ 0 + y = 0

→ y = 0

  • Henceforth, coordinates (0,0)

~ Now let us put y as 0!

→ x + y = 0

→ x + 0 = 0

→ x = 0

  • Henceforth, coordinates (0,0)

Refer to attachment third!

___________________________

For equation y = x – 1 (d)

~ Put x as 0 in equation!

→ y = x - 1

→ y = 0 - 1

→ y = -1

  • Henceforth, coordinates (0,-1)

~ Now put y as 0!

→ y = x - 1

→ 0 = x - 1

→ 0 + 1 = x

→ x = 1

  • Henceforth, coordinates (1,0)

Refer to attachment fourth!

  • According to the graphs we are able to see that equation (c) that is x + y = 0 passes through origin. \:
Attachments:
Answered by amitnrw
1

Given :  Equation of   lines

To Find :  Equation of a line passing through origin  

(a) x+y =1

(b) x=2y-4

(c) x+y=0

(d) y=x-1

Solution:

Equation of a line passing through origin  

Origin ( 0 , 0)

Hence origin will satisfy the equation if line passes through origin

(a) x+y =1

0 + 0  = 1

=> 0 = 1

which is not true

(b) x=2y-4

0 = 2(0) - 4

=> 0 = -4

which is not true

(c) x+y=0

0 + 0 = 0

=> 0 = 0

TRUE

Hence  x+y=0 is Equation of a line passing through origin

(d) y=x-1

0 = 0 - 1

0 = -1

which is not true

Hence correct answer is x+y=0

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