Equation of a line which is 5 units distance above the X axis is
A X=5
B.X+5=Y
c.Y-5
D.X-Y=0
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23
Answer:
(i) The equation of a line parallel to the x-axis at a distance of 5 units above x-axis is y=5.
Step-by-step explanation:
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right answer -Y-5
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4
Given: A line is 5 units distance above the X axis
To find: The equation of the line
Solution: The equation of the X axis is y = 0.
It is known that y = a is the equation of any line parallel to the X axis, where a is the y-intercept of that line.
Here, it has been given that the required line is 5 units distance above the X axis. Hence we can consider 5 to be a for this line, that is, a = 5.
As such, the equation of the required line is y = 5.
Therefore, the equation of a line which is 5 units distance above the X axis is y = 5
⇒ y - 5 = 0.
Answer: Option c. Y-5=0
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