Equation of a straight line is2x + 3y =5 . Slope of the straight line is
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here is the answer of your question
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In general equation of the form, ax + by + c = 0
The slope "m" = (-a/b)
The given equation is 2x + 3y - 5 = 0
Here 'a' = 2, 'b' = 3 & 'c' = (-5)
So the slope "m" = (-2/3)
OR
The given equation is 2x + 3y = 5
=> 3y = (-2x) + 5
=> y = (-2/3x) + 5
Comparing it with slope intercept form y = mx + c
The slope "m" = (-2/3)
Hope it helps !
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