Math, asked by yahoousernk, 3 months ago

equation of a straight line through the piint 2,3 and perpendicular to straight line 4x+7y=9​

Answers

Answered by Rahavram
2

Answer:

7x-4y=2

Step-by-step explanation:

perpendicular to the straight line 4x+7y=9 is

7x-4y+k=0

the required line passing through the point (2,3)

7(2)-4(3)+k=0

14-12+k=0

k=-2

the required equation is

7x-4y-2=0 (or)

7x-4y=2

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