equation of a straight line through the piint 2,3 and perpendicular to straight line 4x+7y=9
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Answer:
7x-4y=2
Step-by-step explanation:
perpendicular to the straight line 4x+7y=9 is
7x-4y+k=0
the required line passing through the point (2,3)
7(2)-4(3)+k=0
14-12+k=0
k=-2
the required equation is
7x-4y-2=0 (or)
7x-4y=2
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