Question

equation of a straight line whose x intercept qnd y intercept are (4,-3)​

Answer 1

Step-by-step explanation:

x/4 + y/-3 = 1

(-3x + 4y) / 12 = 1

-3x + 4y = 12

Answer 2

Answer:

3x - 4y = 12

Step-by-step explanation:

$\frac{x}{4} + \frac{y}{-3} = 1$

$\frac{-3x+4y}{-12} = 1$

- 3x + 4y = - 12

3x - 4y = 12