Question

Equation of alternating current is given by I = 10√2 sin(100πt + π/6). If the time taken by current to reach the root mean square value from t=0 is t', then what is the value of t'?

Answer 1

equation of alternating current is given by , $I=10\sqrt{2}sin(100\pi t+\pi/6)$

where , $I_0=10\sqrt{2}$ A

we know, $I_{av}=\frac{I_0}{\sqrt{2}}$

= $\frac{10\sqrt{2}}{\sqrt{2}}$

= 10A

now, take I = 10A at t = t'

then, 10 = 10√2sin(100πt' + π/6)

or, 1/√2 = sinπ/4 = sin(100πt' + π/6)

or, π/4 = 100πt' + π/6

or, π/12 = 100πt'

or, t' = π/1200π

hence,the value of t' = 1/1200 sec

Answer 2

Answer:

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Explanation:

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