equation of circle x^2+y^2-3x-4y-4=0 which passes through the origin
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The equation of the chord of the circle x^2+y^2-3x-4y-4=0 ,which passes through the origin such that the origin divides into ratio 4:1,is..
Answer:
Equation of the line passing through origin is y = mx
x2 + y2 - 3x - 4y - 4 = 0
x2 + m2 x2 - 3x - 4mx - 4 = 0
Let x1 and x2 be the roots of the equation
x1 + x2 = 3 + 4m/ 1 + m² and x1 x2 = -4/ 1 +m²
x2 = -4x1
Find x1 and x2
you will get y = 0 or y + 24x = 0
If there is any confusion please leave a comment below.
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