Question

equation of circle x^2+y^2-3x-4y-4=0 which passes through the origin

Answer 1

The question seems to be incomplete. Here is the complete question:

The equation of the chord of the circle x^2+y^2-3x-4y-4=0 ,which passes through the origin such that the origin divides into ratio 4:1,is..

Answer:

Equation of the line passing through origin is y = mx

x2 + y2 - 3x - 4y - 4 = 0

x2 + m2 x2 - 3x - 4mx - 4 = 0

Let x1 and x2 be the roots of the equation

x1 + x2 = 3 + 4m/ 1 + m² and x1 x2 = -4/ 1 +m²

x2 = -4x1

Find x1 and x2

you will get y = 0 or y + 24x = 0

If there is any confusion please leave a comment below.