Question

equation of displacement is x = t^3 + 4t^2 - 2t + 5 for moving body in time t where x is in metre and t is in seconds then average acceleration from t= 0 s to t = 4 s is

Answer 1

Answer:

20m/s^2

Explanation:

v=dx/dt=d(t^3+4t^2-2t+5)/dt

=3t^2+8t-2

v at t=0 ,3(0)^2+8(0)-2=-2m/s^2

v at t=4,3(4)^2+8(4)-2=78m/s^2

therefor,acc.av=vf-vi/tf-ti

=72-(-2)/4-0

=80/4 =20 m/s^2