equation of hypotenuse AB of length square root 2 in isosceles triangle OAB is ??
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4
Answer:
EQUATION WILL BE
AB^2= OA^2+OB^2
Step-by-step explanation:
Answered by
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AO² = 1 is the equation of the hypotenuse AB
(Hypotenuse)² = (Height)² + (Base)²
⇒ AB² = AO² + BO²
⇒ AB² = AO² + AB²
since, AO = BO. As its an isosceles triangle.
Let us adding we get,
⇒ AB² = 2AO²
Since the length of the hypotenuse is √2
⇒ (√2)² = 2AO²
⇒ 2 = 2AO²
⇒ AO² = 1
is the equation of the hypotenuse AB of a Isosceles triangle OAB
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