Question

Equation of K2CrO4 as an oxidizing agent in acidic medium is

Answer 1

Answer: K2Cro4 + 8H(+) → 2K(+) + Cr(3+) + 4H2O

Explanation:Here,Cr(+6) is reduced to Cr(+3). So 3 electrons are involved in the reaction

Thus equivalent weight is 294.2÷3=98.6