Question

Equation Of Line Passing Through (1,2) And Perpendicular To 3X+4Y+5=0 Is

Answer 1

Answer:

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Answer 2

Answer:

The Equation of the line is $3y=4x+2$

Step-by-step explanation:

• The equation of the lime given to us is
  $3x+4y+5 = 0$
• Here the slope of the line is $\frac{-3}{4}$
• Hence the line perpendicular to it will have the slope as $\frac{4}{3}$ as the product of the slopes of two perpendicular lines is -1
  $x*\frac{-3}{4} = -1\\x=\frac{4}{3}$
• Hence the equation of the line is $y=mx+c$ and here m is the slope so the equation becomes
  $y=\frac43x+c$
• Now as point (1,2) should satisfy the equation of line
  $2 = 1 * \frac43 +c$
  $2-\frac43 = c\\\frac23 = c$
• So the Equation of the line is $3y=4x+2$
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