Equation of line passing through ( 2,-3) and parallel to the line 4x - y +7 =0 is
Answers
Answered by
0
Answer:
line parallel to 4x - y + 7 = 0
is 4x + y = k
(x,y) = (2,-3)
4(2) -3 = k
k = 5
so the required equation is 4x + y = 5
Step-by-step explanation:
Answered by
1
Answer:
The equation of line passing through ( 2,-3) and parallel to the line 4x - y +7 =0 is y - 4x + 11 = 0
Step-by-step explanation:
Given that the line is parallel to 4x - y + 7 = 0
=> y = 4x + 7
Therefore, the slope of the line is 4
As the line is parallel, it will have the same slope.
The line passes through (2 , -3)
According to equation of the line,
y - y₁ = m (x - x₁)
On substituting the values,
=> y - (-3) = 4 (x - 2)
=> y + 3 = 4x - 8
=> y - 4x + 11 = 0
Therefore, the equation of line passing through ( 2,-3) and parallel to the line 4x - y +7 =0 is y - 4x + 11 = 0
Similar questions