Equation of line passing through (5,0) and perpendicular to y=-3x+4 is
Answers
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0
Answer:
Two perpendicular lines have opposite reciprocal slopes.
The slope in
y
=
3
x
+
4
is
3
, so the line perpendicular to it will have a slope of
−
1
3
.
We can write this in the form
y
=
−
1
3
x
+
b
and then plug in
(
3
,
5
)
for
x
and
y
to find the equation of the line perpendicular to the line
y
=
3
x
+
4
that goes through the point
(
3
,
5
)
.
5
=
−
1
3
(
3
)
+
b
5
=
−
1
+
b
6
=
b
Therefore, the equation of our new line is:
y
=
−
1
3
x
+
6
.
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