Question

Equation of line passing through the points (2, 1) and (3, 1) is

Answer 1

Answer:

Equation of the line passing through (2,1)= x+y=3

Equation of the linr passing through (3,1)= x+y=4

If it helps mark me as brainliest.

Answer 2

• Given, two points are (2,1) and (3,1)

• We have to find a equation which passing through those points.

Solution :

$\blue{ \boxed{\boxed{\begin{array}{cc}\rm \: Equation \: of \: line \: passing \: through \: \\ \rm \: the \: points \: (x_1,y_1) \: \: and \: (x_2,y_2) \: is: \\ \\ \\ \boxed{ \rm \: \frac{x - x_1}{x_1 - x_2} = \frac{y - y_1}{y_1 - y_2} } \\ \\ \end{array}}}}</p><p>$

According to the question,

$x_1 = 2 \\ x_2 = 3 \\ y_1 = 1 \\ y_2 = 1$

So the equation of line is :

$\orange{ \boxed{\boxed{\begin{array}{cc}\rm \: \frac{x - 2}{2 - 3} = \frac{y - 1}{1 - 1} \\ \\ \rm \implies \: \frac{x - 2}{ - 1 } = \frac{y - 1}{0} \\ \\ \rm \implies \: - 1(y - 1) = (x - 2) \times 0 \\ \\ \rm \implies \: - y + 1 = 0 \\ \\ \rm \implies \:y = 1 \end{array}}}}</p><p>$

Finally, Equation of line passing through the points is : y = 1

Which is parallel to X-axis