Question

equation of LINE which is equidistant from 3 X + 4 Y - 5 =0 3 X + 4 Y -13=0 is plzz help

Answer 1

The line is equidistant from

1)3x+4y-5=0
2)3x+4y-13=0
is 3x+4y+k =0
where k is the mean of -5 and -13(constant of (1) and (2)
k= -5-13/2
k=-18/2
k= -9

So the equation of line is


$3x + 4y - 9 = 0$
HOPE THIS HELPED YOU

Answer 2

equation of a line when two points are given
m = (y2-y1)/(x2-x1)
hope you will understand