Question

equation of maximum height when object is thrown vertically upwards with initial velocity u

Answer 1

Explanation:

initial velocity = u

final velocity = v

accⁿ dur to gravity = g

max. height = h

Equation of maximum height when object is thrown vertically upwards

From third equation of motion,

2as = v²-u²

here a(acceleration) = g and s(displacement) = h

so, 2gh = v²-u²

h = $\frac{v²-u²}{2g}$.

Answer 2

Answer:

Explanation:

If a ball travels vertically upwards with the initial velocity u, the maximum height h would be given by the formula: v2 = (u2) + (2* (-g)*h) v2 = (u2) - 2gh. h = (u2 - v2)/2g. where. h is distance in metres,