equation of motion by graphical method long answer this question is impotant for 9 final exam it will surely come in exam answer this question as a long answer❤
Answers
Answer:
Let the initial velocity of the object = u
Let the object is moving with uniform acceleration, a.
Let object reaches at point B after time, t and its final velocity becomes, v
Draw a line parallel to x-axis DA from point, D from where object starts moving.
Draw another line BA from point B parallel to y-axis which meets at E at y-axis.Let OE = time, t
Now, from the graph,
BE = AB + AE
⇒ v = DC + OD (Since, AB = DC and AE = OD)
⇒ v = DC + u (Since, OD = u)
⇒ v = DC + u ------------------- (i)
Now, Acceleration (a)
=
Change in velocity
Time taken
⇒
a
=
v
−
u
t
⇒
a
=
O
C
−
O
D
t
=
D
C
t
⇒
a
t
=
D
C
-----(ii)
By substituting the value of DC from (ii) in (i) we get
v
=
a
t
+
u
⇒
v
=
u
+
a
t
Above equation is the relation among initial vlocity (
u
), final velocity (
v
), acceleration (a) and time (t). It is called first equation of motion
Explanation:
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