Question

Equation of path of any projectile is y = x(1-x). If g = 10 m/s, then find : (a) Projectile angle (ii) Projection velocity (iii) Horizontal range (is) Maximum height​

Answer 1

Answer:

18 m

Explanation:

The equation of trajectory of a projectile is

y=10x− 5/9 x^2

For the range of projectile,

x=R and y=0

0=10R− 5/9 R^2

R(10− 5/9R)=0

10− 5/9 R=0

5R=10×9

R=18m