Question

Equation of SHM is x = 10 sin 10πt. Find the
distance between the two points where speed is
50π cm/sec. x is in cm and t is in seconds.​

Answer 1

Answer:

17

Explanation:

50l-l=100l-lcos10l-lt

t=1/30

x=5×/3

2x=17

Answer 2

The distance between the two points is 8.66 cm

Explanation:

It is given that,

Equation of SHM is given by :

$x=10\ sin(10\pi t)$

Here,

A = 10 cm

Speed, $v=50\pi\ cm/s$

The velocity of a particle in SHM is given by :

$v=\omega\sqrt{(A^2-x^2)}$

Where

A is the amplitude of particle in SHM

x is the distance between the two points

$50\pi =10\pi \sqrt{((10)^2-x^2)}$

$x=8.66\ cm$

So, the distance between the two points is 8.66 cm. Hence, this is the required solution.

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SHM

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