Question

Equation of straight line is 2x +3y = 5. Slope of the straight line is:

Answer 1

In general equation of the form, ax + by + c = 0

The slope "m" = (-a/b)

The given equation is 2x + 3y - 5 = 0

Here 'a' = 2, 'b' = 3 & 'c' = (-5)

So the slope "m" = (-2/3)

OR

The given equation is 2x + 3y = 5

=> 3y = (-2x) + 5

=> y = (-2/3x) + 5

Comparing it with slope intercept form y = mx + c

The slope "m" = (-2/3)

Answer 2

The slope of the straight line is -2/3.

Given,

The equation of a straight line 2x +3y = 5.

To Find,

The slope of the line.

Solution,

The given equation of the line is

2x +3y = 5

Now, the general equation of a straight line is

y = mx + c

where

m is the slope of the line and c is the y-axis intercept.

Now,

2x +3y = 5

3y = 5-2x

y = -2/3x+5/3

So, m = -2/3 and c = 5/3

Hence, the slope of the straight line is -2/3.

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