Equation of straight line whose slope is 3 and which bisects the joint of (-2,5) and (3,4) is?"
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Answered by
9
We have to find the line which bisects the joint of given points (-2,5) and (3,4).
So, The x coordinate of point at which bisection happens is (-2+3)/2=1/2
The y co-ordinate is (5+4)/2=9/2
We know that the point of bisection or contact is (1/2,9/2) which must happen to pass through this line.
Hence, (1/2,9/2) is a solution of the required line.
Now, We know general form of a line with slope m is y = mx + c
Now, Given slope = 3.
y =3x + c
9/2=3(1/2)+c
9/2-3/2=c
6/2=3=c
Now, The equation of line is y =3x+3
3x -y + 3=0 is the required line
So, The x coordinate of point at which bisection happens is (-2+3)/2=1/2
The y co-ordinate is (5+4)/2=9/2
We know that the point of bisection or contact is (1/2,9/2) which must happen to pass through this line.
Hence, (1/2,9/2) is a solution of the required line.
Now, We know general form of a line with slope m is y = mx + c
Now, Given slope = 3.
y =3x + c
9/2=3(1/2)+c
9/2-3/2=c
6/2=3=c
Now, The equation of line is y =3x+3
3x -y + 3=0 is the required line
Answered by
7
Heya...
===== Answer =====
Given ordinate are , ( -2,5) and ( 3,4 )
So it happens as :-
-2+3/2 = 1/2
5+4/2 = 9/2
So we need 1/2 and 9/2 in the solution to bisect. .
Using the y = mx + c
Where slope is 3...
"" y = 3x + c
9/2 = 3(1/2)+c
9/2 - 3/2 = c
6/2 = 3 = c
Equation will be :-
y = 3x + 3
3x = y+ 3 = 0
Thank you
===== Answer =====
Given ordinate are , ( -2,5) and ( 3,4 )
So it happens as :-
-2+3/2 = 1/2
5+4/2 = 9/2
So we need 1/2 and 9/2 in the solution to bisect. .
Using the y = mx + c
Where slope is 3...
"" y = 3x + c
9/2 = 3(1/2)+c
9/2 - 3/2 = c
6/2 = 3 = c
Equation will be :-
y = 3x + 3
3x = y+ 3 = 0
Thank you
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