World Languages, asked by dxjetrate1, 1 year ago

Equation of straight line whose slope is 3 and which bisects the joint of (-2,5) and (3,4) is?"

Answers

Answered by HappiestWriter012
9
We have to find the line which bisects the joint of given points (-2,5) and (3,4). 

So, The x coordinate of point at which bisection happens is (-2+3)/2=1/2 

The y co-ordinate is (5+4)/2=9/2 



We know that the point of bisection or contact is (1/2,9/2) which must happen to pass through this line. 

Hence, (1/2,9/2) is a solution of the required line. 

Now, We know general form of a line with slope m is y = mx + c

Now, Given slope = 3. 

y =3x + c 

9/2=3(1/2)+c 

9/2-3/2=c 
6/2=3=c 

Now, The equation of line is y =3x+3 

3x -y + 3=0 is the required line 

Answered by brainlystargirl
7
Heya...

===== Answer =====

Given ordinate are , ( -2,5) and ( 3,4 )

So it happens as :-

-2+3/2 = 1/2

5+4/2 = 9/2

So we need 1/2 and 9/2 in the solution to bisect. .

Using the y = mx + c
Where slope is 3...

"" y = 3x + c

9/2 = 3(1/2)+c

9/2 - 3/2 = c

6/2 = 3 = c

Equation will be :-

y = 3x + 3

3x = y+ 3 = 0

Thank you
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