Question

Equation of straight line with y intercept + 3/7 perpendicular to 3x + 4y - 7 = 0​

Answer 1

Answer:

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Step-by-step explanation:

$so \: here \\ first \: given \: \: line \: is \\ \: 3x + 4y - 7 = 0 \\ \\ comparing \: it \: with \: \\ ax + by + c = 0 \\ \\ a = 3 \\ b = 4 \\ c = - 7 \\ \\ we \: know \: that \\ \\ slope \: = \frac{ - a}{b} \\ \\ m1= \frac{ - 3}{4}$

$so \: since \: this \: line \: is \: \\ perpendicular \: to \: a \: line \: with \\ y - intercept \: \: as \: \: \frac{3}{7} \\ \\ thus \: then \\ m1 \times m2 = - 1 \\ \\ \frac{ - 3}{4} \times m2 = - 1 \\ \\ m2 = \frac{4}{3}$

$so \: we \: know \: that \\ slope - intercept \: form \: \: equation \: of \\ straight \: line \: is \: \\ \\ y = mx + c \\ \\ y = \frac{4}{3} x + \frac{3}{7} \\ \\ = \frac{(4x \times 7) + (3 \times 3)}{3 \times 7} \\ \\ y = \frac{28 x + 9}{21} \\ \\ 21y = 28x + 9 \\ \\ 28x - 21y + 9 = 0 \\ \\ or \\ \\ 28x - 21y = - 9$