Question

Equation of tangent drawn to the curves y 2 8x and xy=-1

Answer 1

Answer:

Step-by-step explanation:

Answer 2

$\large\underline\mathrm\red{Given:-}$

• Range to the curves y² = 8x is y = mx + 2/m.

• xy = -1

$\large\underline\mathrm\red{Solution}$

x(mx + 2/m) = -1

mx² + 2/m x + 1 = 0

$\large\underline\mathrm\red{Now}$, it has equal roots.

D = 0

4/m² - 4m = 0

m³ = 1

m = 1

$\large\mathrm\red{Hence}$,

Equation of common tangent is

y = x + 2

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