equation of tangent to the circle X square + Y square equal to 4 which is parallel to X + 2 Y + 3 is equal to zero is
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(i)
Let the Equation of tangent parallel to 3x−4y−1=0 be 3x−4y+k=0
Now, Radius = Distance of center from the line
1
2
+2
2
−(−4)
9+16
3(1)−4(2)+k ⇒3∗5=3−8+k⇒k=20
Hence, Equation of tangent parallel to 3x−4y−1=0
is 3x−4y+20=0
(ii)
Let the Equation of tangent perpendicular to 3x−4y−1=0 be 4x+3y+p=0
Now, Radius = Distance of center from the line
1
2
+2
2
−(−4)
16+9
4(1)+3(2)+p
⇒3∗5=4+6+p⇒p=5
Hence, Equation of tangent perpendicular to 3x−4y−1=0
is 4x+3y+5=0
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