Math, asked by Krishna1234upadhyay, 9 months ago

Equation of the circle whose centre is on the line x = 2y and which passes through the points (-1, 2) and
(3,-2) is
(1) x2 + y2 - 12x - 6y - 5 = 0
(2) x + 7 - 4x – 2y + 5 = 0
(3) x2 + y2 - 4x - 2y - 5 = 0
(4) x + y - 8x - 4y - 5 = 0​

Answers

Answered by wasifthegreat786
3

Answer:

Step-by-step explanation:

Revision Notes on Circle

The equation of a circle with its center at C(x0, y0) and radius r is: (x – x0)2 + (y – y0)2 = r2

If x0 = y0 = 0 (i.e. the centre of the circle is at origin) then equation of the circle reduce to x2 + y2 = r2.

If r = 0 then the circle represents a point or a point circle.

The equation x2 + y2 + 2gx + 2fy + c = 0 is the general equation of a circle with centre (–g, –f) and radius √(g2+f2-c).

Equation of the circle with points P(x1, y1) and Q(x2, y2) as extremities of a diameter is (x – x1) (x – x2) + (y – y1)(y – y2) = 0.

For general circle, the equation of the chord is x1x + y1y + g(x1 + x) + f(y1 +y) + c = 0

For circle x2 + y2 = a2, the equation of the chord is x1x + y1y = a2

The equation of the chord AB

(A ≡ (R cos α, R sin α); B ≡ (R cos β, R sin β)) of the circle x2 + y2 = R2 is given by x cos ((α + β )/2) + y sin ((α - β )/2) = a cos ((α - β )/2)

Chords are equidistant from the center of a circle if and only if they are equal in length.

Equal chords of a circle subtend equal angles at the center

Components of Circle

The angle subtended by an arc at the center id double the angle subtended by the same arc at the circumference of the circle.

Angle between the tangent and the radius is 90°.

Angles in the same segment are equal.

Angle in a semi-circle is 90°.

Two angles at the circumference subtended by the same arc are equal.

The below table describes the equations of circle according to changes in radii and centers:

The point P(x1, y1) lies outside, on, or inside a circle ?

S ≡ x2 + y2 + 2gx + 2fy + c = 0, according as S1 ≡ x12 + y12 + 2gx1 + 2fy1 + c > = or < 0.

The equation of the chord of the circle x2 + y2 + 2gx + 2fy +c=0 with M(x1, y1) as the midpoint of the chord is given by:

xx1 + yy1 + g(x + x1) + f(y + y1) = x12 + y12 + 2gx1 + 2fy1 i.e. T = S1

In case the radius and the central angle of a triangle are given, the length of the chord can be computed using the formula

Length of the chord = 2r sin (c/2), where ‘c’ is the central angle and ‘r’ is the radius

Circle with ‘r’ as radius and ‘c’ as the central angle

If a circle has two secants QR and ST, then

circle has two secants

If there is a circle which has one tangent and one secant, then the square of the tangent is equal to the product of the secant segment and its external segment.

If a radius or the diameter of a circle is perpendicular to a chord, then it divides the chord into two equal parts. The converse also holds true.

Hence, in the below figure, if OB is perpendicular to PQ, then then PA = AQ.

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