Equation of the line belonging to the system 3x+2y-8+
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Explanation:
x(3+2λ)+y(2−5λ)−8+λ=0
x(3+2λ)+y(2−5λ)=8−λ
(
3+2λ
8−λ
)
x
+
(
2−5λ
8−λ
)
y
=1 in
A
x
+
B
y
=1 form, where A, B→ intercept
Given, A=B
⇒
3+2λ
8−λ
−
2−5λ
8−λ
⇒3+2λ−2−5λ
⇒7λ=−1
⇒λ=−1/7
⇒ Equation: x(3−
7
2
)+y(2+
7
5
)=8+
7
1
⇒19x+19y=57
⇒x+y=3.
solution
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