Equation of the line passing through the point (2,-3) and has a slope of 3/2
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point=(2,-3) ,slope=3/2
The point slope from is y-y1=m(x-x1)
here, (x1,y1)=(2,-3) and m=3/2
y-(-3)=(3/2)(x-2)
y+3=(3/2)(x-2)
2(y+3)=3(x-2)
2y+6=3x-6
3x-2y-6-6=0
3x-2y-12=0
Here is the solution
Hope this helps u
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