Question

equation of the line passing through the points of intersection of the lines 2x+3y-1=0,3x+4y-6=0 and perpendicular to 5x-2y-7=0 is​

Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

Answer:

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Step by step Answer:

2x + 3y = 1 eq 1

3x + 4y = 6 eq2

eq1× 3 => 6x+9y= 3 eq3

eq2×2=> 6x+8y = 12 eq4

eq3 - eq4 =>

6x+9y=3

-6x- 8y=-12

----------------

0+1y = -9

y= -9

Substitute y value in eq 1

2x + 3(-9) = 1

2x-27=1

2x = 28

X= 28/2

X = 14

Substitute these values of X and Y in 5x - 2y = 7

Then you'll get your Answer...

Finally X= 14 and Y = -9

Hope it helps you

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