Equation of the line PQ is 3x+2y-5=0 write the slope of the line PQ
2) equation of the line AB is 4x-6y=7 find the y-intercept of line AB
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Hi,
1) Compare Equation PQ.
3x+2y-5 =0 with ax+by+c=0
a = 3 , b= 2 , c = -5
Slope of a line ax + by + c =0 is
m.
m = ( -a/ b )
m = ( - 3/2 )
Therefore slope of the line PQ is
m = ( -3/2 )
2 )To find y-intercept of the line put
x= 0 in the given equation.
Equation of the line AB is
4x - 6y = 7
Put x= 0 in above equation ,
4×0-6y =7
-6y = 7
y = ( -7/6 )
Therefore,
Y-intercept of AB is ( -7/6 )
I hope this helps you.
:)
1) Compare Equation PQ.
3x+2y-5 =0 with ax+by+c=0
a = 3 , b= 2 , c = -5
Slope of a line ax + by + c =0 is
m.
m = ( -a/ b )
m = ( - 3/2 )
Therefore slope of the line PQ is
m = ( -3/2 )
2 )To find y-intercept of the line put
x= 0 in the given equation.
Equation of the line AB is
4x - 6y = 7
Put x= 0 in above equation ,
4×0-6y =7
-6y = 7
y = ( -7/6 )
Therefore,
Y-intercept of AB is ( -7/6 )
I hope this helps you.
:)
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