Question

equation of the line through (-9,6) and has a gradient (⅓)

Brainliest question ​

Answer 1

The equation of the line that passes through (-9,6) and has a gradient of -1/3 is 3y + x - 9 = 0

Discussion :

The general form of a straight line equation :

ax + by + c = 0

ax + by = c or

y = mx + c

with:

x and y = variable

a, b, c, and m = constants

↓↓↓↓↓↓

Known :

point (-9, 6)

m = -1/3

Asked: Line equation?

Answer :

Enter m into the equation of the line through point (-9, 6) and gradient -1/3:

y - y₁ = m (x - x₁ )

y - 6 = -1/3 (x - (-9))

y - 6 = -1/3 (x + 9)

y - 6 = -1 / 3x - 3

y = -1 / 3x - 3 + 6

y = -1 / 3x + 3

Because the result is a fraction, then the two segments we multiply by 3, then:

3y = -x + 9

3y + x - 9 = 0

Answer 2

Answer:

the formula of one point and slope is y-y1 = m(x-x1)

point(x1,y1) = (-9,6)

m = 1/3

substitute in equation

y-6 = 1/3 ( x+9)

3y-18 = x+9

x-3y+27=0 is answer