Question

equation of the perpendicular bisector of the line segment joining (5,7),(3,1) is

Answer 1

let A = (5,7)
B = (3,1)

midpoint of A and B
= ( 5+3/2 , 7+1/2)
= (8/2 , 8/2)
= (4,4)

slope of AB = (1-7)/(3-5) =-6/-2 = 3

slope of the perpendicular = -1/3

the perpendicular passes through (4,4)

the equation ,

y - 4 = -1/3 (x-4)

3y - 12 = -x + 4

3y + x = 16